1100201313403 has 2 divisors, whose sum is σ = 1100201313404. Its totient is φ = 1100201313402.

The previous prime is 1100201313397. The next prime is 1100201313557. The reversal of 1100201313403 is 3043131020011.

It is a weak prime.

It is an emirp because it is prime and its reverse (3043131020011) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1100201313403 - 2²¹ = 1100199216251 is a prime.

It is not a weakly prime, because it can be changed into another prime (1100201313803) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 550100656701 + 550100656702.

It is an arithmetic number, because the mean of its divisors is an integer number (550100656702).

Almost surely, 2^{1100201313403} is an apocalyptic number.

1100201313403 is a deficient number, since it is larger than the sum of its proper divisors (1).

1100201313403 is an equidigital number, since it uses as much as digits as its factorization.

1100201313403 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 216, while the sum is 19.

Adding to 1100201313403 its reverse (3043131020011), we get a palindrome (4143332333414).

The spelling of 1100201313403 in words is "one trillion, one hundred billion, two hundred one million, three hundred thirteen thousand, four hundred three".