Base | Representation |
---|---|
bin | 11001000001000000001110… |
… | …111001111000110011111011 |
3 | 112102112211012012001002221002 |
4 | 121001000032321320303323 |
5 | 103410032212332412032 |
6 | 1025554315005035215 |
7 | 32113456304365634 |
oct | 3101001671706373 |
9 | 472484165032832 |
10 | 110020132310267 |
11 | 32068304519943 |
12 | 1040a77b855b0b |
13 | 4950b141c329a |
14 | 1d25007a2888b |
15 | cabd21db6862 |
hex | 64100ee78cfb |
110020132310267 has 2 divisors, whose sum is σ = 110020132310268. Its totient is φ = 110020132310266.
The previous prime is 110020132310243. The next prime is 110020132310327. The reversal of 110020132310267 is 762013231020011.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-110020132310267 is a prime.
It is a super-2 number, since 2×1100201323102672 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (110020132310167) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55010066155133 + 55010066155134.
It is an arithmetic number, because the mean of its divisors is an integer number (55010066155134).
Almost surely, 2110020132310267 is an apocalyptic number.
110020132310267 is a deficient number, since it is larger than the sum of its proper divisors (1).
110020132310267 is an equidigital number, since it uses as much as digits as its factorization.
110020132310267 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 3024, while the sum is 29.
Adding to 110020132310267 its reverse (762013231020011), we get a palindrome (872033363330278).
The spelling of 110020132310267 in words is "one hundred ten trillion, twenty billion, one hundred thirty-two million, three hundred ten thousand, two hundred sixty-seven".
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