Base | Representation |
---|---|
bin | 10100011111100010… |
… | …11000000100100011 |
3 | 1001101202020112100002 |
4 | 22033301120010203 |
5 | 140013004121011 |
6 | 5015415250215 |
7 | 536432425304 |
oct | 121761300443 |
9 | 31352215302 |
10 | 11002020131 |
11 | 4736398623 |
12 | 217067996b |
13 | 1064483cab |
14 | 7652787ab |
15 | 445d3cc3b |
hex | 28fc58123 |
11002020131 has 2 divisors, whose sum is σ = 11002020132. Its totient is φ = 11002020130.
The previous prime is 11002019983. The next prime is 11002020149. The reversal of 11002020131 is 13102020011.
It is a strong prime.
It is an emirp because it is prime and its reverse (13102020011) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 11002020131 - 210 = 11002019107 is a prime.
It is a super-2 number, since 2×110020201312 (a number of 21 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (11002020181) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5501010065 + 5501010066.
It is an arithmetic number, because the mean of its divisors is an integer number (5501010066).
Almost surely, 211002020131 is an apocalyptic number.
11002020131 is a deficient number, since it is larger than the sum of its proper divisors (1).
11002020131 is an equidigital number, since it uses as much as digits as its factorization.
11002020131 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 12, while the sum is 11.
Adding to 11002020131 its reverse (13102020011), we get a palindrome (24104040142).
The spelling of 11002020131 in words is "eleven billion, two million, twenty thousand, one hundred thirty-one".
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