Base | Representation |
---|---|
bin | 1010000000011001110001… |
… | …0001101000110010001001 |
3 | 1102221210011121022120202011 |
4 | 2200012130101220302021 |
5 | 2420224130434123444 |
6 | 35222133024135521 |
7 | 2213604431314162 |
oct | 240063421506211 |
9 | 42853147276664 |
10 | 11002033114249 |
11 | 3561a32963821 |
12 | 12983267675a1 |
13 | 61a6446c3a38 |
14 | 2a07035b0769 |
15 | 1412c4e0d734 |
hex | a019c468c89 |
11002033114249 has 2 divisors, whose sum is σ = 11002033114250. Its totient is φ = 11002033114248.
The previous prime is 11002033114243. The next prime is 11002033114349. The reversal of 11002033114249 is 94241133020011.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 6941433315600 + 4060599798649 = 2634660^2 + 2015093^2 .
It is a cyclic number.
It is not a de Polignac number, because 11002033114249 - 221 = 11002031017097 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 11002033114249.
It is not a weakly prime, because it can be changed into another prime (11002033114243) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5501016557124 + 5501016557125.
It is an arithmetic number, because the mean of its divisors is an integer number (5501016557125).
Almost surely, 211002033114249 is an apocalyptic number.
It is an amenable number.
11002033114249 is a deficient number, since it is larger than the sum of its proper divisors (1).
11002033114249 is an equidigital number, since it uses as much as digits as its factorization.
11002033114249 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5184, while the sum is 31.
The spelling of 11002033114249 in words is "eleven trillion, two billion, thirty-three million, one hundred fourteen thousand, two hundred forty-nine".
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