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11002101200212 = 222750525300053
BaseRepresentation
bin1010000000011010000001…
…0101010111010101010100
31102221210100100102201010111
42200012200111113111110
52420224300401401322
635222143455332404
72213606216116423
oct240064025272524
942853310381114
1011002101200212
113561a68337811
121298345521104
1361a6558422a5
142a070c6552ba
151412cadac177
hexa01a0557554

11002101200212 has 6 divisors (see below), whose sum is σ = 19253677100378. Its totient is φ = 5501050600104.

The previous prime is 11002101200179. The next prime is 11002101200239. The reversal of 11002101200212 is 21200210120011.

It can be written as a sum of positive squares in only one way, i.e., 6570629928976 + 4431471271236 = 2563324^2 + 2105106^2 .

It is a super-3 number, since 3×110021012002123 (a number of 40 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 11002101200192 and 11002101200201.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1375262650023 + ... + 1375262650030.

Almost surely, 211002101200212 is an apocalyptic number.

It is an amenable number.

11002101200212 is a deficient number, since it is larger than the sum of its proper divisors (8251575900166).

11002101200212 is a wasteful number, since it uses less digits than its factorization.

11002101200212 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2750525300057 (or 2750525300055 counting only the distinct ones).

The product of its (nonzero) digits is 16, while the sum is 13.

Adding to 11002101200212 its reverse (21200210120011), we get a palindrome (32202311320223).

The spelling of 11002101200212 in words is "eleven trillion, two billion, one hundred one million, two hundred thousand, two hundred twelve".

Divisors: 1 2 4 2750525300053 5501050600106 11002101200212