Base | Representation |
---|---|
bin | 11001000001000001000011… |
… | …111000101111011001010010 |
3 | 112102112220111010122111011012 |
4 | 121001001003320233121102 |
5 | 103410041022411431002 |
6 | 1025554543121050522 |
7 | 32113520320011011 |
oct | 3101010370573122 |
9 | 472486433574135 |
10 | 110021021202002 |
11 | 32068720254409 |
12 | 1040a989486a42 |
13 | 4950c263ca821 |
14 | 1d2508dad2a78 |
15 | cabd74e4bd52 |
hex | 641043e2f652 |
110021021202002 has 4 divisors (see below), whose sum is σ = 165031531803006. Its totient is φ = 55010510601000.
The previous prime is 110021021201939. The next prime is 110021021202031. The reversal of 110021021202002 is 200202120120011.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 59795438028001 + 50225583174001 = 7732751^2 + 7087001^2 .
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27505255300499 + ... + 27505255300502.
Almost surely, 2110021021202002 is an apocalyptic number.
110021021202002 is a deficient number, since it is larger than the sum of its proper divisors (55010510601004).
110021021202002 is an equidigital number, since it uses as much as digits as its factorization.
110021021202002 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 55010510601003.
The product of its (nonzero) digits is 32, while the sum is 14.
Adding to 110021021202002 its reverse (200202120120011), we get a palindrome (310223141322013).
The spelling of 110021021202002 in words is "one hundred ten trillion, twenty-one billion, twenty-one million, two hundred two thousand, two".
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