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110021022011122 = 255010511005561
BaseRepresentation
bin11001000001000001000011…
…111011110100111011110010
3112102112220111012011121001121
4121001001003323310323302
5103410041023113323442
61025554543150252454
732113520326620655
oct3101010373647362
9472486435147047
10110021022011122
1132068720757302
121040a9897b712a
134950c26621bb1
141d2508dc6389c
15cabd7505b967
hex641043ef4ef2

110021022011122 has 4 divisors (see below), whose sum is σ = 165031533016686. Its totient is φ = 55010511005560.

The previous prime is 110021022011113. The next prime is 110021022011167. The reversal of 110021022011122 is 221110220120011.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 91137399721281 + 18883622289841 = 9546591^2 + 4345529^2 .

It is a super-2 number, since 2×1100210220111222 (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 110021022011096 and 110021022011105.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27505255502779 + ... + 27505255502782.

Almost surely, 2110021022011122 is an apocalyptic number.

110021022011122 is a deficient number, since it is larger than the sum of its proper divisors (55010511005564).

110021022011122 is an equidigital number, since it uses as much as digits as its factorization.

110021022011122 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 55010511005563.

The product of its (nonzero) digits is 32, while the sum is 16.

Adding to 110021022011122 its reverse (221110220120011), we get a palindrome (331131242131133).

The spelling of 110021022011122 in words is "one hundred ten trillion, twenty-one billion, twenty-two million, eleven thousand, one hundred twenty-two".

Divisors: 1 2 55010511005561 110021022011122