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1100211022153 is a prime number
BaseRepresentation
bin10000000000101001101…
…011111110100101001001
310220011211121010210201001
4100000221223332211021
5121011213010202103
62201232512255001
7142326153246325
oct20005153764511
93804747123631
101100211022153
11394662492071
1215928a541461
137c998721459
143b371518985
151d94428601d
hex10029afe949

1100211022153 has 2 divisors, whose sum is σ = 1100211022154. Its totient is φ = 1100211022152.

The previous prime is 1100211022109. The next prime is 1100211022217. The reversal of 1100211022153 is 3512201120011.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 753340674304 + 346870347849 = 867952^2 + 588957^2 .

It is a cyclic number.

It is not a de Polignac number, because 1100211022153 - 225 = 1100177467721 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 1100211022153.

It is not a weakly prime, because it can be changed into another prime (1100211022553) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 550105511076 + 550105511077.

It is an arithmetic number, because the mean of its divisors is an integer number (550105511077).

Almost surely, 21100211022153 is an apocalyptic number.

It is an amenable number.

1100211022153 is a deficient number, since it is larger than the sum of its proper divisors (1).

1100211022153 is an equidigital number, since it uses as much as digits as its factorization.

1100211022153 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 120, while the sum is 19.

Adding to 1100211022153 its reverse (3512201120011), we get a palindrome (4612412142164).

The spelling of 1100211022153 in words is "one trillion, one hundred billion, two hundred eleven million, twenty-two thousand, one hundred fifty-three".