Search a number
-
+
110021213320507 is a prime number
BaseRepresentation
bin11001000001000001001111…
…010101100111010100111011
3112102112220222112011010012101
4121001001033111213110323
5103410041421102224012
61025555014142524231
732113525142001166
oct3101011725472473
9472486875133171
10110021213320507
1132068809743935
121040aa21896677
134950c57155608
141d250ab422add
15cabd86c4ad57
hex64104f56753b

110021213320507 has 2 divisors, whose sum is σ = 110021213320508. Its totient is φ = 110021213320506.

The previous prime is 110021213320391. The next prime is 110021213320531. The reversal of 110021213320507 is 705023312120011.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 110021213320507 - 231 = 110019065836859 is a prime.

It is not a weakly prime, because it can be changed into another prime (110021213320807) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55010606660253 + 55010606660254.

It is an arithmetic number, because the mean of its divisors is an integer number (55010606660254).

Almost surely, 2110021213320507 is an apocalyptic number.

110021213320507 is a deficient number, since it is larger than the sum of its proper divisors (1).

110021213320507 is an equidigital number, since it uses as much as digits as its factorization.

110021213320507 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2520, while the sum is 28.

Adding to 110021213320507 its reverse (705023312120011), we get a palindrome (815044525440518).

The spelling of 110021213320507 in words is "one hundred ten trillion, twenty-one billion, two hundred thirteen million, three hundred twenty thousand, five hundred seven".