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110021221020122 = 255010610510061
BaseRepresentation
bin11001000001000001001111…
…110010111111000111011010
3112102112221000001122022002022
4121001001033302333013122
5103410041430040120442
61025555015015534442
732113525264310066
oct3101011762770732
9472487001568068
10110021221020122
1132068813022755
121040aa2438a422
134950c589200b9
141d250ac468aa6
15cabd8776c3d2
hex64104fcbf1da

110021221020122 has 4 divisors (see below), whose sum is σ = 165031831530186. Its totient is φ = 55010610510060.

The previous prime is 110021221020119. The next prime is 110021221020181. The reversal of 110021221020122 is 221020122120011.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 75608085574681 + 34413135445441 = 8695291^2 + 5866271^2 .

It is a super-3 number, since 3×1100212210201223 (a number of 43 digits) contains 333 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 110021221020122.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27505305255029 + ... + 27505305255032.

Almost surely, 2110021221020122 is an apocalyptic number.

110021221020122 is a deficient number, since it is larger than the sum of its proper divisors (55010610510064).

110021221020122 is an equidigital number, since it uses as much as digits as its factorization.

110021221020122 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 55010610510063.

The product of its (nonzero) digits is 64, while the sum is 17.

Adding to 110021221020122 its reverse (221020122120011), we get a palindrome (331041343140133).

The spelling of 110021221020122 in words is "one hundred ten trillion, twenty-one billion, two hundred twenty-one million, twenty thousand, one hundred twenty-two".

Divisors: 1 2 55010610510061 110021221020122