Base | Representation |
---|---|
bin | 110011001110111001… |
… | …0001001100001011001 |
3 | 101111222120120202010212 |
4 | 1212131302021201121 |
5 | 3300310431222023 |
6 | 122313151220505 |
7 | 10643301025523 |
oct | 1463562114131 |
9 | 344876522125 |
10 | 110021351513 |
11 | 42729203897 |
12 | 193a5b17735 |
13 | a4b4a64538 |
14 | 5479d80a13 |
15 | 2cdde13e78 |
hex | 199dc89859 |
110021351513 has 2 divisors, whose sum is σ = 110021351514. Its totient is φ = 110021351512.
The previous prime is 110021351509. The next prime is 110021351563. The reversal of 110021351513 is 315153120011.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 109807402384 + 213949129 = 331372^2 + 14627^2 .
It is an emirp because it is prime and its reverse (315153120011) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 110021351513 - 22 = 110021351509 is a prime.
It is not a weakly prime, because it can be changed into another prime (110021351563) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55010675756 + 55010675757.
It is an arithmetic number, because the mean of its divisors is an integer number (55010675757).
Almost surely, 2110021351513 is an apocalyptic number.
It is an amenable number.
110021351513 is a deficient number, since it is larger than the sum of its proper divisors (1).
110021351513 is an equidigital number, since it uses as much as digits as its factorization.
110021351513 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 450, while the sum is 23.
Adding to 110021351513 its reverse (315153120011), we get a palindrome (425174471524).
The spelling of 110021351513 in words is "one hundred ten billion, twenty-one million, three hundred fifty-one thousand, five hundred thirteen".
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