Base | Representation |
---|---|
bin | 1010000000011010001010… |
… | …1011000001111100100110 |
3 | 1102221210110002021000001200 |
4 | 2200012202223001330212 |
5 | 2420224340422343324 |
6 | 35222151420303330 |
7 | 2213610203444316 |
oct | 240064253017446 |
9 | 42853402230050 |
10 | 11002140434214 |
11 | 3561a884a4906 |
12 | 12983566a1b46 |
13 | 61a6609cb287 |
14 | 2a0713949446 |
15 | 1412ce55bec9 |
hex | a01a2ac1f26 |
11002140434214 has 48 divisors (see below), whose sum is σ = 24015342639600. Its totient is φ = 3640127855040.
The previous prime is 11002140434209. The next prime is 11002140434287. The reversal of 11002140434214 is 41243404120011.
11002140434214 is a `hidden beast` number, since 1 + 1 + 0 + 0 + 2 + 14 + 0 + 434 + 214 = 666.
It is a Curzon number.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 2218609 + ... + 5189075.
It is an arithmetic number, because the mean of its divisors is an integer number (500319638325).
Almost surely, 211002140434214 is an apocalyptic number.
11002140434214 is an abundant number, since it is smaller than the sum of its proper divisors (13013202205386).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
11002140434214 is a wasteful number, since it uses less digits than its factorization.
11002140434214 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2972005 (or 2972002 counting only the distinct ones).
The product of its (nonzero) digits is 3072, while the sum is 27.
Adding to 11002140434214 its reverse (41243404120011), we get a palindrome (52245544554225).
The spelling of 11002140434214 in words is "eleven trillion, two billion, one hundred forty million, four hundred thirty-four thousand, two hundred fourteen".
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