Base | Representation |
---|---|
bin | 10000000000101010001… |
… | …110001101001011000001 |
3 | 10220011212020000122212221 |
4 | 100000222032031023001 |
5 | 121011222304313232 |
6 | 2201233432451041 |
7 | 142326322436566 |
oct | 20005216151301 |
9 | 3804766018787 |
10 | 1100219994817 |
11 | 394667560399 |
12 | 159291549a81 |
13 | 7c99a543518 |
14 | 3b3727b286d |
15 | 1d944e59897 |
hex | 1002a38d2c1 |
1100219994817 has 2 divisors, whose sum is σ = 1100219994818. Its totient is φ = 1100219994816.
The previous prime is 1100219994799. The next prime is 1100219994883. The reversal of 1100219994817 is 7184999120011.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 888766249536 + 211453745281 = 942744^2 + 459841^2 .
It is a cyclic number.
It is not a de Polignac number, because 1100219994817 - 235 = 1065860256449 is a prime.
It is not a weakly prime, because it can be changed into another prime (1100219994217) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 550109997408 + 550109997409.
It is an arithmetic number, because the mean of its divisors is an integer number (550109997409).
Almost surely, 21100219994817 is an apocalyptic number.
It is an amenable number.
1100219994817 is a deficient number, since it is larger than the sum of its proper divisors (1).
1100219994817 is an equidigital number, since it uses as much as digits as its factorization.
1100219994817 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 326592, while the sum is 52.
The spelling of 1100219994817 in words is "one trillion, one hundred billion, two hundred nineteen million, nine hundred ninety-four thousand, eight hundred seventeen".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.074 sec. • engine limits •