11002201213 has 4 divisors (see below), whose sum is σ = 11002411008. Its totient is φ = 11001991420.

The previous prime is 11002201207. The next prime is 11002201229. The reversal of 11002201213 is 31210220011.

11002201213 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also a brilliant number, because the two primes have the same length, and also an emirpimes, since its reverse is a distinct semiprime: 31210220011 = 61 ⋅511642951.

It is a cyclic number.

It is not a de Polignac number, because 11002201213 - 2⁵ = 11002201181 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11002201193 and 11002201202.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11002201913) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 50820 + ... + 156802.

It is an arithmetic number, because the mean of its divisors is an integer number (2750602752).

Almost surely, 2^11002201213 is an apocalyptic number.

It is an amenable number.

11002201213 is a deficient number, since it is larger than the sum of its proper divisors (209795).

11002201213 is a wasteful number, since it uses less digits than its factorization.

11002201213 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 209794.

The product of its (nonzero) digits is 24, while the sum is 13.

Adding to 11002201213 its reverse (31210220011), we get a palindrome (42212421224).

The spelling of 11002201213 in words is "eleven billion, two million, two hundred one thousand, two hundred thirteen".