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1100220134045 = 51631471348747
BaseRepresentation
bin10000000000101010001…
…110101111001010011101
310220011212020021201212112
4100000222032233022131
5121011222323242140
62201233435443405
7142326323556524
oct20005216571235
93804766251775
101100220134045
11394667645a5a
121592915b6565
137c99a5919c6
143b37280b4bb
151d944e85c65
hex1002a3af29d

1100220134045 has 8 divisors (see below), whose sum is σ = 1320273232224. Its totient is φ = 880170059664.

The previous prime is 1100220134033. The next prime is 1100220134053. The reversal of 1100220134045 is 5404310220011.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 1100220134045 - 24 = 1100220134029 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 1100220134045.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 141362 + ... + 1490108.

It is an arithmetic number, because the mean of its divisors is an integer number (165034154028).

Almost surely, 21100220134045 is an apocalyptic number.

It is an amenable number.

1100220134045 is a deficient number, since it is larger than the sum of its proper divisors (220053098179).

1100220134045 is a wasteful number, since it uses less digits than its factorization.

1100220134045 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1511899.

The product of its (nonzero) digits is 960, while the sum is 23.

Adding to 1100220134045 its reverse (5404310220011), we get a palindrome (6504530354056).

The spelling of 1100220134045 in words is "one trillion, one hundred billion, two hundred twenty million, one hundred thirty-four thousand, forty-five".

Divisors: 1 5 163147 815735 1348747 6743735 220044026809 1100220134045