1100220134033 has 2 divisors, whose sum is σ = 1100220134034. Its totient is φ = 1100220134032.

The previous prime is 1100220134029. The next prime is 1100220134053. The reversal of 1100220134033 is 3304310220011.

It is an a-pointer prime, because the next prime (1100220134053) can be obtained adding 1100220134033 to its sum of digits (20).

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1031102146624 + 69117987409 = 1015432^2 + 262903^2 .

It is a cyclic number.

It is not a de Polignac number, because 1100220134033 - 2² = 1100220134029 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1100220133996 and 1100220134014.

It is not a weakly prime, because it can be changed into another prime (1100220134053) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 550110067016 + 550110067017.

It is an arithmetic number, because the mean of its divisors is an integer number (550110067017).

Almost surely, 2^{1100220134033} is an apocalyptic number.

It is an amenable number.

1100220134033 is a deficient number, since it is larger than the sum of its proper divisors (1).

1100220134033 is an equidigital number, since it uses as much as digits as its factorization.

1100220134033 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 432, while the sum is 20.

Adding to 1100220134033 its reverse (3304310220011), we get a palindrome (4404530354044).

The spelling of 1100220134033 in words is "one trillion, one hundred billion, two hundred twenty million, one hundred thirty-four thousand, thirty-three".