11002201403 has 2 divisors, whose sum is σ = 11002201404. Its totient is φ = 11002201402.

The previous prime is 11002201391. The next prime is 11002201421. The reversal of 11002201403 is 30410220011.

11002201403 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is an emirp because it is prime and its reverse (30410220011) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 11002201403 - 2¹⁸ = 11001939259 is a prime.

It is a Sophie Germain prime.

It is not a weakly prime, because it can be changed into another prime (11002201433) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5501100701 + 5501100702.

It is an arithmetic number, because the mean of its divisors is an integer number (5501100702).

Almost surely, 2^11002201403 is an apocalyptic number.

11002201403 is a deficient number, since it is larger than the sum of its proper divisors (1).

11002201403 is an equidigital number, since it uses as much as digits as its factorization.

11002201403 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 48, while the sum is 14.

Adding to 11002201403 its reverse (30410220011), we get a palindrome (41412421414).

The spelling of 11002201403 in words is "eleven billion, two million, two hundred one thousand, four hundred three".