Base | Representation |
---|---|
bin | 110011001110111010… |
… | …1000000110000000001 |
3 | 101111222121222212122022 |
4 | 1212131311000300001 |
5 | 3300311124231032 |
6 | 122313215251225 |
7 | 10643310302552 |
oct | 1463565006001 |
9 | 344877885568 |
10 | 110022102017 |
11 | 42729676743 |
12 | 193a6219b15 |
13 | a4b4c68019 |
14 | 547a0d8329 |
15 | 2cde011512 |
hex | 199dd40c01 |
110022102017 has 2 divisors, whose sum is σ = 110022102018. Its totient is φ = 110022102016.
The previous prime is 110022102011. The next prime is 110022102053. The reversal of 110022102017 is 710201220011.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 94344808336 + 15677293681 = 307156^2 + 125209^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-110022102017 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 110022101986 and 110022102004.
It is not a weakly prime, because it can be changed into another prime (110022102011) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55011051008 + 55011051009.
It is an arithmetic number, because the mean of its divisors is an integer number (55011051009).
Almost surely, 2110022102017 is an apocalyptic number.
It is an amenable number.
110022102017 is a deficient number, since it is larger than the sum of its proper divisors (1).
110022102017 is an equidigital number, since it uses as much as digits as its factorization.
110022102017 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 56, while the sum is 17.
Adding to 110022102017 its reverse (710201220011), we get a palindrome (820223322028).
The spelling of 110022102017 in words is "one hundred ten billion, twenty-two million, one hundred two thousand, seventeen".
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