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110022102017 is a prime number
BaseRepresentation
bin110011001110111010…
…1000000110000000001
3101111222121222212122022
41212131311000300001
53300311124231032
6122313215251225
710643310302552
oct1463565006001
9344877885568
10110022102017
1142729676743
12193a6219b15
13a4b4c68019
14547a0d8329
152cde011512
hex199dd40c01

110022102017 has 2 divisors, whose sum is σ = 110022102018. Its totient is φ = 110022102016.

The previous prime is 110022102011. The next prime is 110022102053. The reversal of 110022102017 is 710201220011.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 94344808336 + 15677293681 = 307156^2 + 125209^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-110022102017 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 110022101986 and 110022102004.

It is not a weakly prime, because it can be changed into another prime (110022102011) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55011051008 + 55011051009.

It is an arithmetic number, because the mean of its divisors is an integer number (55011051009).

Almost surely, 2110022102017 is an apocalyptic number.

It is an amenable number.

110022102017 is a deficient number, since it is larger than the sum of its proper divisors (1).

110022102017 is an equidigital number, since it uses as much as digits as its factorization.

110022102017 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 56, while the sum is 17.

Adding to 110022102017 its reverse (710201220011), we get a palindrome (820223322028).

The spelling of 110022102017 in words is "one hundred ten billion, twenty-two million, one hundred two thousand, seventeen".