Base | Representation |
---|---|
bin | 10000000000101011011… |
… | …100001101011100010001 |
3 | 10220011220122111112201201 |
4 | 100000223130031130101 |
5 | 121011243023140103 |
6 | 2201235443031201 |
7 | 142326661313665 |
oct | 20005334153421 |
9 | 3804818445651 |
10 | 1100240443153 |
11 | 394678057545 |
12 | 15929836b501 |
13 | 7c9a1852a27 |
14 | 3b3753b68a5 |
15 | 1d946b4851d |
hex | 1002b70d711 |
1100240443153 has 2 divisors, whose sum is σ = 1100240443154. Its totient is φ = 1100240443152.
The previous prime is 1100240443123. The next prime is 1100240443187. The reversal of 1100240443153 is 3513440420011.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1095480409104 + 4760034049 = 1046652^2 + 68993^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1100240443153 is a prime.
It is not a weakly prime, because it can be changed into another prime (1100240443103) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 550120221576 + 550120221577.
It is an arithmetic number, because the mean of its divisors is an integer number (550120221577).
Almost surely, 21100240443153 is an apocalyptic number.
It is an amenable number.
1100240443153 is a deficient number, since it is larger than the sum of its proper divisors (1).
1100240443153 is an equidigital number, since it uses as much as digits as its factorization.
1100240443153 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5760, while the sum is 28.
Adding to 1100240443153 its reverse (3513440420011), we get a palindrome (4613680863164).
The spelling of 1100240443153 in words is "one trillion, one hundred billion, two hundred forty million, four hundred forty-three thousand, one hundred fifty-three".
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