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1100240443153 is a prime number
BaseRepresentation
bin10000000000101011011…
…100001101011100010001
310220011220122111112201201
4100000223130031130101
5121011243023140103
62201235443031201
7142326661313665
oct20005334153421
93804818445651
101100240443153
11394678057545
1215929836b501
137c9a1852a27
143b3753b68a5
151d946b4851d
hex1002b70d711

1100240443153 has 2 divisors, whose sum is σ = 1100240443154. Its totient is φ = 1100240443152.

The previous prime is 1100240443123. The next prime is 1100240443187. The reversal of 1100240443153 is 3513440420011.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1095480409104 + 4760034049 = 1046652^2 + 68993^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1100240443153 is a prime.

It is not a weakly prime, because it can be changed into another prime (1100240443103) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 550120221576 + 550120221577.

It is an arithmetic number, because the mean of its divisors is an integer number (550120221577).

Almost surely, 21100240443153 is an apocalyptic number.

It is an amenable number.

1100240443153 is a deficient number, since it is larger than the sum of its proper divisors (1).

1100240443153 is an equidigital number, since it uses as much as digits as its factorization.

1100240443153 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 5760, while the sum is 28.

Adding to 1100240443153 its reverse (3513440420011), we get a palindrome (4613680863164).

The spelling of 1100240443153 in words is "one trillion, one hundred billion, two hundred forty million, four hundred forty-three thousand, one hundred fifty-three".