Base | Representation |
---|---|
bin | 10000000000101011100… |
… | …110011110011111000010 |
3 | 10220011220211120021102121 |
4 | 100000223212132133002 |
5 | 121011244220300102 |
6 | 2201240020434454 |
7 | 142330023223126 |
oct | 20005346363702 |
9 | 3804824507377 |
10 | 1100243134402 |
11 | 394679625515 |
12 | 159299248a2a |
13 | 7c9a2285999 |
14 | 3b3758b7586 |
15 | 1d946ecab37 |
hex | 1002b99e7c2 |
1100243134402 has 4 divisors (see below), whose sum is σ = 1650364701606. Its totient is φ = 550121567200.
The previous prime is 1100243134343. The next prime is 1100243134411. The reversal of 1100243134402 is 2044313420011.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 582262089721 + 517981044681 = 763061^2 + 719709^2 .
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 275060783599 + ... + 275060783602.
Almost surely, 21100243134402 is an apocalyptic number.
1100243134402 is a deficient number, since it is larger than the sum of its proper divisors (550121567204).
1100243134402 is an equidigital number, since it uses as much as digits as its factorization.
1100243134402 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 550121567203.
The product of its (nonzero) digits is 2304, while the sum is 25.
Adding to 1100243134402 its reverse (2044313420011), we get a palindrome (3144556554413).
The spelling of 1100243134402 in words is "one trillion, one hundred billion, two hundred forty-three million, one hundred thirty-four thousand, four hundred two".
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