11002511053130 has 16 divisors (see below), whose sum is σ = 19851561518184. Its totient is φ = 4390550727360.

The previous prime is 11002511053117. The next prime is 11002511053253. The reversal of 11002511053130 is 3135011520011.

It can be written as a sum of positive squares in 4 ways, for example, as 2217576657409 + 8784934395721 = 1489153^2 + 2963939^2 .

It is a junction number, because it is equal to n+sod(n) for n = 11002511053096 and 11002511053105.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1306707317 + ... + 1306715736.

Almost surely, 2^{11002511053130} is an apocalyptic number.

11002511053130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

11002511053130 is a deficient number, since it is larger than the sum of its proper divisors (8849050465054).

11002511053130 is a wasteful number, since it uses less digits than its factorization.

11002511053130 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2613423481.

The product of its (nonzero) digits is 450, while the sum is 23.

Adding to 11002511053130 its reverse (3135011520011), we get a palindrome (14137522573141).

The spelling of 11002511053130 in words is "eleven trillion, two billion, five hundred eleven million, fifty-three thousand, one hundred thirty".