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1100310213313 is a prime number
BaseRepresentation
bin10000000000101111100…
…110010111001011000001
310220012002111210020101201
4100000233212113023001
5121011413403311223
62201250414301201
7142331466332353
oct20005746271301
93805074706351
101100310213313
11394703480933
121592b77b7801
137c9b3140a4c
143b3807790d3
151d94cd2aead
hex1002f9972c1

1100310213313 has 2 divisors, whose sum is σ = 1100310213314. Its totient is φ = 1100310213312.

The previous prime is 1100310213259. The next prime is 1100310213323. The reversal of 1100310213313 is 3133120130011.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 563172200704 + 537138012609 = 750448^2 + 732897^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1100310213313 is a prime.

It is not a weakly prime, because it can be changed into another prime (1100310213323) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 550155106656 + 550155106657.

It is an arithmetic number, because the mean of its divisors is an integer number (550155106657).

Almost surely, 21100310213313 is an apocalyptic number.

It is an amenable number.

1100310213313 is a deficient number, since it is larger than the sum of its proper divisors (1).

1100310213313 is an equidigital number, since it uses as much as digits as its factorization.

1100310213313 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 162, while the sum is 19.

Adding to 1100310213313 its reverse (3133120130011), we get a palindrome (4233430343324).

The spelling of 1100310213313 in words is "one trillion, one hundred billion, three hundred ten million, two hundred thirteen thousand, three hundred thirteen".