Base | Representation |
---|---|
bin | 11001000001001010011101… |
… | …001110111000010001001011 |
3 | 112102120212112020201020022201 |
4 | 121001022131032320101023 |
5 | 103410222203142043311 |
6 | 1030003332201301031 |
7 | 32114325324226522 |
oct | 3101123516702113 |
9 | 472525466636281 |
10 | 110031110112331 |
11 | 32071a28176031 |
12 | 10410924194777 |
13 | 4951b73647c55 |
14 | 1d2576999b4b9 |
15 | cac265a1d9c1 |
hex | 64129d3b844b |
110031110112331 has 2 divisors, whose sum is σ = 110031110112332. Its totient is φ = 110031110112330.
The previous prime is 110031110112289. The next prime is 110031110112361. The reversal of 110031110112331 is 133211011130011.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 110031110112331 - 215 = 110031110079563 is a prime.
It is a super-2 number, since 2×1100311101123312 (a number of 29 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 110031110112299 and 110031110112308.
It is not a weakly prime, because it can be changed into another prime (110031110112361) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55015555056165 + 55015555056166.
It is an arithmetic number, because the mean of its divisors is an integer number (55015555056166).
Almost surely, 2110031110112331 is an apocalyptic number.
110031110112331 is a deficient number, since it is larger than the sum of its proper divisors (1).
110031110112331 is an equidigital number, since it uses as much as digits as its factorization.
110031110112331 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 54, while the sum is 19.
Adding to 110031110112331 its reverse (133211011130011), we get a palindrome (243242121242342).
The spelling of 110031110112331 in words is "one hundred ten trillion, thirty-one billion, one hundred ten million, one hundred twelve thousand, three hundred thirty-one".
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