Base | Representation |
---|---|
bin | 10000000000101111101… |
… | …101100100010011111001 |
3 | 10220012002122100012101011 |
4 | 100000233231210103321 |
5 | 121011414344232022 |
6 | 2201250522553521 |
7 | 142331521360213 |
oct | 20005755442371 |
9 | 3805078305334 |
10 | 1100312102137 |
11 | 394704550a46 |
12 | 1592b83688a1 |
13 | 7c9b36526b1 |
14 | 3b380b0b5b3 |
15 | 1d94d0a0977 |
hex | 1002fb644f9 |
1100312102137 has 2 divisors, whose sum is σ = 1100312102138. Its totient is φ = 1100312102136.
The previous prime is 1100312102107. The next prime is 1100312102143. The reversal of 1100312102137 is 7312012130011.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1100088420201 + 223681936 = 1048851^2 + 14956^2 .
It is a cyclic number.
It is not a de Polignac number, because 1100312102137 - 223 = 1100303713529 is a prime.
It is not a weakly prime, because it can be changed into another prime (1100312102107) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 550156051068 + 550156051069.
It is an arithmetic number, because the mean of its divisors is an integer number (550156051069).
Almost surely, 21100312102137 is an apocalyptic number.
It is an amenable number.
1100312102137 is a deficient number, since it is larger than the sum of its proper divisors (1).
1100312102137 is an equidigital number, since it uses as much as digits as its factorization.
1100312102137 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 252, while the sum is 22.
Adding to 1100312102137 its reverse (7312012130011), we get a palindrome (8412324232148).
The spelling of 1100312102137 in words is "one trillion, one hundred billion, three hundred twelve million, one hundred two thousand, one hundred thirty-seven".
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