Base | Representation |
---|---|
bin | 110011001111001100… |
… | …0001011100011100011 |
3 | 101112000021100021010210 |
4 | 1212132120023203203 |
5 | 3300321004240230 |
6 | 122314145025203 |
7 | 10643451541146 |
oct | 1463630134343 |
9 | 345007307123 |
10 | 110031321315 |
11 | 427338a32a3 |
12 | 193a9325203 |
13 | a4b6b45426 |
14 | 547b41805d |
15 | 2cdec32eb0 |
hex | 199e60b8e3 |
110031321315 has 32 divisors (see below), whose sum is σ = 181329603840. Its totient is φ = 56932689024.
The previous prime is 110031321313. The next prime is 110031321319. The reversal of 110031321315 is 513123130011.
It is not a de Polignac number, because 110031321315 - 21 = 110031321313 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 110031321291 and 110031321300.
It is not an unprimeable number, because it can be changed into a prime (110031321313) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 93085 + ... + 478254.
It is an arithmetic number, because the mean of its divisors is an integer number (5666550120).
Almost surely, 2110031321315 is an apocalyptic number.
110031321315 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
110031321315 is a deficient number, since it is larger than the sum of its proper divisors (71298282525).
110031321315 is a wasteful number, since it uses less digits than its factorization.
110031321315 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 571731.
The product of its (nonzero) digits is 270, while the sum is 21.
Adding to 110031321315 its reverse (513123130011), we get a palindrome (623154451326).
The spelling of 110031321315 in words is "one hundred ten billion, thirty-one million, three hundred twenty-one thousand, three hundred fifteen".
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