Base | Representation |
---|---|
bin | 110011001111001100… |
… | …0001011100011100111 |
3 | 101112000021100021010221 |
4 | 1212132120023203213 |
5 | 3300321004240234 |
6 | 122314145025211 |
7 | 10643451541153 |
oct | 1463630134347 |
9 | 345007307127 |
10 | 110031321319 |
11 | 427338a32a7 |
12 | 193a9325207 |
13 | a4b6b4542a |
14 | 547b418063 |
15 | 2cdec32eb4 |
hex | 199e60b8e7 |
110031321319 has 2 divisors, whose sum is σ = 110031321320. Its totient is φ = 110031321318.
The previous prime is 110031321313. The next prime is 110031321329. The reversal of 110031321319 is 913123130011.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 110031321319 - 221 = 110029224167 is a prime.
It is a super-2 number, since 2×1100313213192 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 110031321293 and 110031321302.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (110031321313) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55015660659 + 55015660660.
It is an arithmetic number, because the mean of its divisors is an integer number (55015660660).
Almost surely, 2110031321319 is an apocalyptic number.
110031321319 is a deficient number, since it is larger than the sum of its proper divisors (1).
110031321319 is an equidigital number, since it uses as much as digits as its factorization.
110031321319 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 486, while the sum is 25.
The spelling of 110031321319 in words is "one hundred ten billion, thirty-one million, three hundred twenty-one thousand, three hundred nineteen".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.068 sec. • engine limits •