110032003300013 has 4 divisors (see below), whose sum is σ = 110032108743900. Its totient is φ = 110031897856128.

The previous prime is 110032003299931. The next prime is 110032003300019. The reversal of 110032003300013 is 310003300230011.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 104278347152329 + 5753656147684 = 10211677^2 + 2398678^2 .

It is a cyclic number.

It is not a de Polignac number, because 110032003300013 - 2¹⁰ = 110032003298989 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 110032003299964 and 110032003300000.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (110032003300019) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 51140870 + ... + 53248967.

It is an arithmetic number, because the mean of its divisors is an integer number (27508027185975).

Almost surely, 2^{110032003300013} is an apocalyptic number.

It is an amenable number.

110032003300013 is a deficient number, since it is larger than the sum of its proper divisors (105443887).

110032003300013 is a wasteful number, since it uses less digits than its factorization.

110032003300013 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 105443886.

The product of its (nonzero) digits is 162, while the sum is 17.

Adding to 110032003300013 its reverse (310003300230011), we get a palindrome (420035303530024).

The spelling of 110032003300013 in words is "one hundred ten trillion, thirty-two billion, three million, three hundred thousand, thirteen".