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110032003298989 is a prime number
BaseRepresentation
bin11001000001001011010010…
…011110000111011010101101
3112102120221211111101211002001
4121001023102132013122231
5103410231020321031424
61030004000545332301
732114356421210332
oct3101132236073255
9472527744354061
10110032003298989
1132072346374422
1210410b33337091
134951c866c7375
141d25812462989
15cac2b9151844
hex6412d27876ad

110032003298989 has 2 divisors, whose sum is σ = 110032003298990. Its totient is φ = 110032003298988.

The previous prime is 110032003298957. The next prime is 110032003298999. The reversal of 110032003298989 is 989892300230011.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 108783961302025 + 1248041996964 = 10429955^2 + 1117158^2 .

It is a cyclic number.

It is not a de Polignac number, because 110032003298989 - 25 = 110032003298957 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (110032003298999) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55016001649494 + 55016001649495.

It is an arithmetic number, because the mean of its divisors is an integer number (55016001649495).

Almost surely, 2110032003298989 is an apocalyptic number.

It is an amenable number.

110032003298989 is a deficient number, since it is larger than the sum of its proper divisors (1).

110032003298989 is an equidigital number, since it uses as much as digits as its factorization.

110032003298989 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1679616, while the sum is 55.

The spelling of 110032003298989 in words is "one hundred ten trillion, thirty-two billion, three million, two hundred ninety-eight thousand, nine hundred eighty-nine".