Base | Representation |
---|---|
bin | 10000000000110000001… |
… | …100001101101101110011 |
3 | 10220012010012110100211112 |
4 | 100000300030031231303 |
5 | 121011423423323201 |
6 | 2201251411103535 |
7 | 142331646560543 |
oct | 20006014155563 |
9 | 3805105410745 |
10 | 1100320136051 |
11 | 394709038a44 |
12 | 1592baba1bab |
13 | 7c9b52063a6 |
14 | 3b381bdd323 |
15 | 1d94db3b0bb |
hex | 1003030db73 |
1100320136051 has 2 divisors, whose sum is σ = 1100320136052. Its totient is φ = 1100320136050.
The previous prime is 1100320136009. The next prime is 1100320136087. The reversal of 1100320136051 is 1506310230011.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1100320136051 - 26 = 1100320135987 is a prime.
It is a super-2 number, since 2×11003201360512 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1100320130051) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 550160068025 + 550160068026.
It is an arithmetic number, because the mean of its divisors is an integer number (550160068026).
Almost surely, 21100320136051 is an apocalyptic number.
1100320136051 is a deficient number, since it is larger than the sum of its proper divisors (1).
1100320136051 is an equidigital number, since it uses as much as digits as its factorization.
1100320136051 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 540, while the sum is 23.
Adding to 1100320136051 its reverse (1506310230011), we get a palindrome (2606630366062).
The spelling of 1100320136051 in words is "one trillion, one hundred billion, three hundred twenty million, one hundred thirty-six thousand, fifty-one".
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