1100321211331 has 2 divisors, whose sum is σ = 1100321211332. Its totient is φ = 1100321211330.

The previous prime is 1100321211317. The next prime is 1100321211343. The reversal of 1100321211331 is 1331121230011.

It is a strong prime.

It is an emirp because it is prime and its reverse (1331121230011) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1100321211331 - 2⁵ = 1100321211299 is a prime.

It is a super-2 number, since 2×1100321211331² (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1100321211299 and 1100321211308.

It is not a weakly prime, because it can be changed into another prime (1100321211131) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 550160605665 + 550160605666.

It is an arithmetic number, because the mean of its divisors is an integer number (550160605666).

Almost surely, 2^{1100321211331} is an apocalyptic number.

1100321211331 is a deficient number, since it is larger than the sum of its proper divisors (1).

1100321211331 is an equidigital number, since it uses as much as digits as its factorization.

1100321211331 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 108, while the sum is 19.

Adding to 1100321211331 its reverse (1331121230011), we get a palindrome (2431442441342).

The spelling of 1100321211331 in words is "one trillion, one hundred billion, three hundred twenty-one million, two hundred eleven thousand, three hundred thirty-one".