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1100330010193 is a prime number
BaseRepresentation
bin10000000000110000110…
…001111000011001010001
310220012010220001000121111
4100000300301320121101
5121011433440311233
62201252402453321
7142332126524251
oct20006061703121
93805126030544
101100330010193
11394713672597
12159302364241
137c9b728288b
143b38324d961
151d94e93bacd
hex10030c78651

1100330010193 has 2 divisors, whose sum is σ = 1100330010194. Its totient is φ = 1100330010192.

The previous prime is 1100330010119. The next prime is 1100330010209. The reversal of 1100330010193 is 3910100330011.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 808798046224 + 291531963969 = 899332^2 + 539937^2 .

It is an emirp because it is prime and its reverse (3910100330011) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1100330010193 - 213 = 1100330002001 is a prime.

It is a super-2 number, since 2×11003300101932 (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1100330010113) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 550165005096 + 550165005097.

It is an arithmetic number, because the mean of its divisors is an integer number (550165005097).

Almost surely, 21100330010193 is an apocalyptic number.

It is an amenable number.

1100330010193 is a deficient number, since it is larger than the sum of its proper divisors (1).

1100330010193 is an equidigital number, since it uses as much as digits as its factorization.

1100330010193 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 243, while the sum is 22.

The spelling of 1100330010193 in words is "one trillion, one hundred billion, three hundred thirty million, ten thousand, one hundred ninety-three".