Base | Representation |
---|---|
bin | 10000000000110000110… |
… | …001111000011001010001 |
3 | 10220012010220001000121111 |
4 | 100000300301320121101 |
5 | 121011433440311233 |
6 | 2201252402453321 |
7 | 142332126524251 |
oct | 20006061703121 |
9 | 3805126030544 |
10 | 1100330010193 |
11 | 394713672597 |
12 | 159302364241 |
13 | 7c9b728288b |
14 | 3b38324d961 |
15 | 1d94e93bacd |
hex | 10030c78651 |
1100330010193 has 2 divisors, whose sum is σ = 1100330010194. Its totient is φ = 1100330010192.
The previous prime is 1100330010119. The next prime is 1100330010209. The reversal of 1100330010193 is 3910100330011.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 808798046224 + 291531963969 = 899332^2 + 539937^2 .
It is an emirp because it is prime and its reverse (3910100330011) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1100330010193 - 213 = 1100330002001 is a prime.
It is a super-2 number, since 2×11003300101932 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1100330010113) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 550165005096 + 550165005097.
It is an arithmetic number, because the mean of its divisors is an integer number (550165005097).
Almost surely, 21100330010193 is an apocalyptic number.
It is an amenable number.
1100330010193 is a deficient number, since it is larger than the sum of its proper divisors (1).
1100330010193 is an equidigital number, since it uses as much as digits as its factorization.
1100330010193 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 243, while the sum is 22.
The spelling of 1100330010193 in words is "one trillion, one hundred billion, three hundred thirty million, ten thousand, one hundred ninety-three".
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