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110033224034113 is a prime number
BaseRepresentation
bin11001000001001100011011…
…001110110110011101000001
3112102121001222120102120212001
4121001030123032312131001
5103410241020323042423
61030004322034104001
732114431603246012
oct3101143316663501
9472531876376761
10110033224034113
1132072912452826
121041121411b001
13495211c59b743
141d258ca62d009
15cac33b3d5cad
hex64131b3b6741

110033224034113 has 2 divisors, whose sum is σ = 110033224034114. Its totient is φ = 110033224034112.

The previous prime is 110033224034101. The next prime is 110033224034147. The reversal of 110033224034113 is 311430422330011.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 109286785057024 + 746438977089 = 10454032^2 + 863967^2 .

It is a cyclic number.

It is not a de Polignac number, because 110033224034113 - 233 = 110024634099521 is a prime.

It is not a weakly prime, because it can be changed into another prime (110033224032113) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55016612017056 + 55016612017057.

It is an arithmetic number, because the mean of its divisors is an integer number (55016612017057).

Almost surely, 2110033224034113 is an apocalyptic number.

It is an amenable number.

110033224034113 is a deficient number, since it is larger than the sum of its proper divisors (1).

110033224034113 is an equidigital number, since it uses as much as digits as its factorization.

110033224034113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 5184, while the sum is 28.

Adding to 110033224034113 its reverse (311430422330011), we get a palindrome (421463646364124).

The spelling of 110033224034113 in words is "one hundred ten trillion, thirty-three billion, two hundred twenty-four million, thirty-four thousand, one hundred thirteen".