Base | Representation |
---|---|
bin | 10100011111101101… |
… | …01111001000110111 |
3 | 1001101211212220220200 |
4 | 22033312233020313 |
5 | 140013334102320 |
6 | 5015505331543 |
7 | 536450400150 |
oct | 121766571067 |
9 | 31354786820 |
10 | 11003425335 |
11 | 4737168351 |
12 | 2171036bb3 |
13 | 1064856786 |
14 | 765522927 |
15 | 446019290 |
hex | 28fdaf237 |
11003425335 has 48 divisors (see below), whose sum is σ = 22073226240. Its totient is φ = 4966453440.
The previous prime is 11003425327. The next prime is 11003425337. The reversal of 11003425335 is 53352430011.
It is not a de Polignac number, because 11003425335 - 23 = 11003425327 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 11003425299 and 11003425308.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11003425337) by changing a digit.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 196201 + ... + 245970.
It is an arithmetic number, because the mean of its divisors is an integer number (459858880).
Almost surely, 211003425335 is an apocalyptic number.
11003425335 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
11003425335 is an abundant number, since it is smaller than the sum of its proper divisors (11069800905).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
11003425335 is a wasteful number, since it uses less digits than its factorization.
11003425335 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 442268 (or 442265 counting only the distinct ones).
The product of its (nonzero) digits is 5400, while the sum is 27.
Adding to 11003425335 its reverse (53352430011), we get a palindrome (64355855346).
The spelling of 11003425335 in words is "eleven billion, three million, four hundred twenty-five thousand, three hundred thirty-five".
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