11004043411 has 2 divisors, whose sum is σ = 11004043412. Its totient is φ = 11004043410.

The previous prime is 11004043403. The next prime is 11004043429. The reversal of 11004043411 is 11434040011.

It is a weak prime.

It is an emirp because it is prime and its reverse (11434040011) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 11004043411 - 2³ = 11004043403 is a prime.

It is not a weakly prime, because it can be changed into another prime (11004043481) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5502021705 + 5502021706.

It is an arithmetic number, because the mean of its divisors is an integer number (5502021706).

Almost surely, 2^11004043411 is an apocalyptic number.

11004043411 is a deficient number, since it is larger than the sum of its proper divisors (1).

11004043411 is an equidigital number, since it uses as much as digits as its factorization.

11004043411 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 192, while the sum is 19.

Adding to 11004043411 its reverse (11434040011), we get a palindrome (22438083422).

The spelling of 11004043411 in words is "eleven billion, four million, forty-three thousand, four hundred eleven".