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110041040232401 is a prime number
BaseRepresentation
bin11001000001010011101101…
…000111010001111111010001
3112102121211011021222121012112
4121001103231013101333101
5103410403022244414101
61030012053410235105
732115126362655065
oct3101235507217721
9472554137877175
10110041040232401
11320761634a1233
1210412835885a95
134952a96a09445
141d2602c72daa5
15cac6476c66bb
hex6414ed1d1fd1

110041040232401 has 2 divisors, whose sum is σ = 110041040232402. Its totient is φ = 110041040232400.

The previous prime is 110041040232377. The next prime is 110041040232469. The reversal of 110041040232401 is 104232040140011.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 104135902090000 + 5905138142401 = 10204700^2 + 2430049^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-110041040232401 is a prime.

It is not a weakly prime, because it can be changed into another prime (110041040232001) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55020520116200 + 55020520116201.

It is an arithmetic number, because the mean of its divisors is an integer number (55020520116201).

Almost surely, 2110041040232401 is an apocalyptic number.

It is an amenable number.

110041040232401 is a deficient number, since it is larger than the sum of its proper divisors (1).

110041040232401 is an equidigital number, since it uses as much as digits as its factorization.

110041040232401 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 768, while the sum is 23.

Adding to 110041040232401 its reverse (104232040140011), we get a palindrome (214273080372412).

The spelling of 110041040232401 in words is "one hundred ten trillion, forty-one billion, forty million, two hundred thirty-two thousand, four hundred one".