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11004121341 = 321222680149
BaseRepresentation
bin10100011111110010…
…11001000011111101
31001101220012021122200
422033321121003331
5140014023340331
65015532302113
7536456326263
oct121771310375
931356167580
1011004121341
1147375a3264
122171311939
131064a3b505
14765664433
154461055e6
hex28fe590fd

11004121341 has 6 divisors (see below), whose sum is σ = 15894841950. Its totient is φ = 7336080888.

The previous prime is 11004121319. The next prime is 11004121351. The reversal of 11004121341 is 14312140011.

It can be written as a sum of positive squares in only one way, i.e., 10968372900 + 35748441 = 104730^2 + 5979^2 .

It is not a de Polignac number, because 11004121341 - 26 = 11004121277 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11004121351) by changing a digit.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 611340066 + ... + 611340083.

It is an arithmetic number, because the mean of its divisors is an integer number (2649140325).

Almost surely, 211004121341 is an apocalyptic number.

It is an amenable number.

11004121341 is a deficient number, since it is larger than the sum of its proper divisors (4890720609).

11004121341 is a wasteful number, since it uses less digits than its factorization.

11004121341 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1222680155 (or 1222680152 counting only the distinct ones).

The product of its (nonzero) digits is 96, while the sum is 18.

Adding to 11004121341 its reverse (14312140011), we get a palindrome (25316261352).

The spelling of 11004121341 in words is "eleven billion, four million, one hundred twenty-one thousand, three hundred forty-one".

Divisors: 1 3 9 1222680149 3668040447 11004121341