Base | Representation |
---|---|
bin | 1010000000100001100101… |
… | …1101110000101000000101 |
3 | 1102221222120222110101122200 |
4 | 2200020121131300220011 |
5 | 2420242431130202401 |
6 | 35223121253345113 |
7 | 2214010453653630 |
oct | 240103135605005 |
9 | 42858528411580 |
10 | 11004133444101 |
11 | 35629104a7716 |
12 | 1298812038199 |
13 | 61a8ba898a75 |
14 | 2a0862504c17 |
15 | 1413994dd686 |
hex | a0219770a05 |
11004133444101 has 24 divisors (see below), whose sum is σ = 18176857805184. Its totient is φ = 6284163267360.
The previous prime is 11004133444099. The next prime is 11004133444127. The reversal of 11004133444101 is 10144433140011.
11004133444101 is a `hidden beast` number, since 1 + 100 + 4 + 13 + 3 + 444 + 101 = 666.
It is not a de Polignac number, because 11004133444101 - 21 = 11004133444099 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11004133444141) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 54244990 + ... + 54447471.
It is an arithmetic number, because the mean of its divisors is an integer number (757369075216).
Almost surely, 211004133444101 is an apocalyptic number.
It is an amenable number.
11004133444101 is a deficient number, since it is larger than the sum of its proper divisors (7172724361083).
11004133444101 is a wasteful number, since it uses less digits than its factorization.
11004133444101 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 108694081 (or 108694078 counting only the distinct ones).
The product of its (nonzero) digits is 2304, while the sum is 27.
Adding to 11004133444101 its reverse (10144433140011), we get a palindrome (21148566584112).
The spelling of 11004133444101 in words is "eleven trillion, four billion, one hundred thirty-three million, four hundred forty-four thousand, one hundred one".
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