Search a number
-
+
110041355549921 is a prime number
BaseRepresentation
bin11001000001010011111111…
…111010000111110011100001
3112102121211222021022101112012
4121001103333322013303201
5103410404144010044141
61030012144552442305
732115140242062125
oct3101237772076341
9472554867271465
10110041355549921
1132076305487a24
12104129033a9395
134952b1713b263
141d2605c56d585
15cac66520dceb
hex6414ffe87ce1

110041355549921 has 2 divisors, whose sum is σ = 110041355549922. Its totient is φ = 110041355549920.

The previous prime is 110041355549893. The next prime is 110041355549927. The reversal of 110041355549921 is 129945553140011.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 109256428656400 + 784926893521 = 10452580^2 + 885961^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-110041355549921 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is a self number, because there is not a number n which added to its sum of digits gives 110041355549921.

It is not a weakly prime, because it can be changed into another prime (110041355549927) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55020677774960 + 55020677774961.

It is an arithmetic number, because the mean of its divisors is an integer number (55020677774961).

Almost surely, 2110041355549921 is an apocalyptic number.

It is an amenable number.

110041355549921 is a deficient number, since it is larger than the sum of its proper divisors (1).

110041355549921 is an equidigital number, since it uses as much as digits as its factorization.

110041355549921 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 972000, while the sum is 50.

The spelling of 110041355549921 in words is "one hundred ten trillion, forty-one billion, three hundred fifty-five million, five hundred forty-nine thousand, nine hundred twenty-one".