Base | Representation |
---|---|
bin | 1010000000100001100110… |
… | …0101110011111110111010 |
3 | 1102221222121010102122021012 |
4 | 2200020121211303332322 |
5 | 2420242432200230002 |
6 | 35223121410513522 |
7 | 2214010510625102 |
oct | 240103145637672 |
9 | 42858533378235 |
10 | 11004135555002 |
11 | 3562911709667 |
12 | 12988128958a2 |
13 | 61a8bb157815 |
14 | 2a08628d4202 |
15 | 1413997a8d52 |
hex | a0219973fba |
11004135555002 has 8 divisors (see below), whose sum is σ = 16908793657812. Its totient is φ = 5367871002400.
The previous prime is 11004135554989. The next prime is 11004135555019. The reversal of 11004135555002 is 20055553140011.
11004135555002 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It can be written as a sum of positive squares in 2 ways, for example, as 10858929593521 + 145205961481 = 3295289^2 + 381059^2 .
It is a sphenic number, since it is the product of 3 distinct primes.
It is a self number, because there is not a number n which added to its sum of digits gives 11004135555002.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 67098387449 + ... + 67098387612.
Almost surely, 211004135555002 is an apocalyptic number.
11004135555002 is a deficient number, since it is larger than the sum of its proper divisors (5904658102810).
11004135555002 is a wasteful number, since it uses less digits than its factorization.
11004135555002 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 134196775104.
The product of its (nonzero) digits is 15000, while the sum is 32.
Adding to 11004135555002 its reverse (20055553140011), we get a palindrome (31059688695013).
The spelling of 11004135555002 in words is "eleven trillion, four billion, one hundred thirty-five million, five hundred fifty-five thousand, two".
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