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11004135555002 = 241134196775061
BaseRepresentation
bin1010000000100001100110…
…0101110011111110111010
31102221222121010102122021012
42200020121211303332322
52420242432200230002
635223121410513522
72214010510625102
oct240103145637672
942858533378235
1011004135555002
113562911709667
1212988128958a2
1361a8bb157815
142a08628d4202
151413997a8d52
hexa0219973fba

11004135555002 has 8 divisors (see below), whose sum is σ = 16908793657812. Its totient is φ = 5367871002400.

The previous prime is 11004135554989. The next prime is 11004135555019. The reversal of 11004135555002 is 20055553140011.

11004135555002 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It can be written as a sum of positive squares in 2 ways, for example, as 10858929593521 + 145205961481 = 3295289^2 + 381059^2 .

It is a sphenic number, since it is the product of 3 distinct primes.

It is a self number, because there is not a number n which added to its sum of digits gives 11004135555002.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 67098387449 + ... + 67098387612.

Almost surely, 211004135555002 is an apocalyptic number.

11004135555002 is a deficient number, since it is larger than the sum of its proper divisors (5904658102810).

11004135555002 is a wasteful number, since it uses less digits than its factorization.

11004135555002 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 134196775104.

The product of its (nonzero) digits is 15000, while the sum is 32.

Adding to 11004135555002 its reverse (20055553140011), we get a palindrome (31059688695013).

The spelling of 11004135555002 in words is "eleven trillion, four billion, one hundred thirty-five million, five hundred fifty-five thousand, two".

Divisors: 1 2 41 82 134196775061 268393550122 5502067777501 11004135555002