1100424131123 has 2 divisors, whose sum is σ = 1100424131124. Its totient is φ = 1100424131122.

The previous prime is 1100424131021. The next prime is 1100424131167. The reversal of 1100424131123 is 3211314240011.

It is a strong prime.

It is an emirp because it is prime and its reverse (3211314240011) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1100424131123 - 2¹² = 1100424127027 is a prime.

It is a super-3 number, since 3×1100424131123³ (a number of 37 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is not a weakly prime, because it can be changed into another prime (1100424131423) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 550212065561 + 550212065562.

It is an arithmetic number, because the mean of its divisors is an integer number (550212065562).

Almost surely, 2^{1100424131123} is an apocalyptic number.

1100424131123 is a deficient number, since it is larger than the sum of its proper divisors (1).

1100424131123 is an equidigital number, since it uses as much as digits as its factorization.

1100424131123 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 576, while the sum is 23.

Adding to 1100424131123 its reverse (3211314240011), we get a palindrome (4311738371134).

The spelling of 1100424131123 in words is "one trillion, one hundred billion, four hundred twenty-four million, one hundred thirty-one thousand, one hundred twenty-three".