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1100433130102 = 24133133127647
BaseRepresentation
bin10000000000110110111…
…011010000001001110110
310220012102002002001112101
4100000312323100021312
5121012141340130402
62201310525012314
7142334521162345
oct20006673201166
93805362061471
101100433130102
113947668a5059
121593309b409a
137ca02749487
143b392c13b5c
151d958a0ab87
hex10036ed0276

1100433130102 has 8 divisors (see below), whose sum is σ = 1651049090496. Its totient is φ = 550083433272.

The previous prime is 1100433130099. The next prime is 1100433130109. The reversal of 1100433130102 is 2010313340011.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a self number, because there is not a number n which added to its sum of digits gives 1100433130102.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1100433130109) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 66555558 + ... + 66572089.

It is an arithmetic number, because the mean of its divisors is an integer number (206381136312).

Almost surely, 21100433130102 is an apocalyptic number.

1100433130102 is a deficient number, since it is larger than the sum of its proper divisors (550615960394).

1100433130102 is a wasteful number, since it uses less digits than its factorization.

1100433130102 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 133131782.

The product of its (nonzero) digits is 216, while the sum is 19.

Adding to 1100433130102 its reverse (2010313340011), we get a palindrome (3110746470113).

The spelling of 1100433130102 in words is "one trillion, one hundred billion, four hundred thirty-three million, one hundred thirty thousand, one hundred two".

Divisors: 1 2 4133 8266 133127647 266255294 550216565051 1100433130102