Base | Representation |
---|---|
bin | 10100011111110100… |
… | …10010001110111001 |
3 | 1001101220122011212201 |
4 | 22033322102032321 |
5 | 140014103334023 |
6 | 5015541310201 |
7 | 536461323064 |
oct | 121772221671 |
9 | 31356564781 |
10 | 11004355513 |
11 | 4737743198 |
12 | 2171405361 |
13 | 1064ac0c88 |
14 | 7656c58db |
15 | 44614ebad |
hex | 28fe923b9 |
11004355513 has 2 divisors, whose sum is σ = 11004355514. Its totient is φ = 11004355512.
The previous prime is 11004355487. The next prime is 11004355547. The reversal of 11004355513 is 31555340011.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 8665375744 + 2338979769 = 93088^2 + 48363^2 .
It is a cyclic number.
It is not a de Polignac number, because 11004355513 - 221 = 11002258361 is a prime.
It is not a weakly prime, because it can be changed into another prime (11004355553) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5502177756 + 5502177757.
It is an arithmetic number, because the mean of its divisors is an integer number (5502177757).
Almost surely, 211004355513 is an apocalyptic number.
It is an amenable number.
11004355513 is a deficient number, since it is larger than the sum of its proper divisors (1).
11004355513 is an equidigital number, since it uses as much as digits as its factorization.
11004355513 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 4500, while the sum is 28.
Adding to 11004355513 its reverse (31555340011), we get a palindrome (42559695524).
The spelling of 11004355513 in words is "eleven billion, four million, three hundred fifty-five thousand, five hundred thirteen".
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