Base | Representation |
---|---|
bin | 1010000000100010100110… |
… | …0010100011010101111011 |
3 | 1102222000021202221011012121 |
4 | 2200020221202203111323 |
5 | 2420244004200321432 |
6 | 35223204130022111 |
7 | 2214020240212201 |
oct | 240105142432573 |
9 | 42860252834177 |
10 | 11004403135867 |
11 | 3562a39760079 |
12 | 1298888417937 |
13 | 61a9317144ab |
14 | 2a088a269071 |
15 | 1413b3012197 |
hex | a02298a357b |
11004403135867 has 2 divisors, whose sum is σ = 11004403135868. Its totient is φ = 11004403135866.
The previous prime is 11004403135861. The next prime is 11004403135907. The reversal of 11004403135867 is 76853130440011.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11004403135867 is a prime.
It is not a weakly prime, because it can be changed into another prime (11004403135861) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5502201567933 + 5502201567934.
It is an arithmetic number, because the mean of its divisors is an integer number (5502201567934).
Almost surely, 211004403135867 is an apocalyptic number.
11004403135867 is a deficient number, since it is larger than the sum of its proper divisors (1).
11004403135867 is an equidigital number, since it uses as much as digits as its factorization.
11004403135867 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 241920, while the sum is 43.
Adding to 11004403135867 its reverse (76853130440011), we get a palindrome (87857533575878).
The spelling of 11004403135867 in words is "eleven trillion, four billion, four hundred three million, one hundred thirty-five thousand, eight hundred sixty-seven".
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