Base | Representation |
---|---|
bin | 10100011111111001… |
… | …11101001001001101 |
3 | 1001101221221202011120 |
4 | 22033330331021031 |
5 | 140014243234230 |
6 | 5020004311153 |
7 | 536500300050 |
oct | 121774751115 |
9 | 31357852146 |
10 | 11005055565 |
11 | 4738081149 |
12 | 21716a24b9 |
13 | 1064ca77ca |
14 | 765828a97 |
15 | 44623c310 |
hex | 28ff3d24d |
11005055565 has 16 divisors (see below), whose sum is σ = 20123530368. Its totient is φ = 5030882496.
The previous prime is 11005055563. The next prime is 11005055597. The reversal of 11005055565 is 56555050011.
It is not a de Polignac number, because 11005055565 - 21 = 11005055563 is a prime.
It is a super-2 number, since 2×110050555652 (a number of 21 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11005055561) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 52404922 + ... + 52405131.
It is an arithmetic number, because the mean of its divisors is an integer number (1257720648).
Almost surely, 211005055565 is an apocalyptic number.
11005055565 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
It is an amenable number.
11005055565 is a deficient number, since it is larger than the sum of its proper divisors (9118474803).
11005055565 is a wasteful number, since it uses less digits than its factorization.
11005055565 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 104810068.
The product of its (nonzero) digits is 18750, while the sum is 33.
The spelling of 11005055565 in words is "eleven billion, five million, fifty-five thousand, five hundred sixty-five".
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