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11005055597 is a prime number
BaseRepresentation
bin10100011111111001…
…11101001001101101
31001101221221202012202
422033330331021231
5140014243234342
65020004311245
7536500300124
oct121774751155
931357852182
1011005055597
114738081178
1221716a2525
131064ca7823
14765828abb
1544623c332
hex28ff3d26d

11005055597 has 2 divisors, whose sum is σ = 11005055598. Its totient is φ = 11005055596.

The previous prime is 11005055563. The next prime is 11005055639. The reversal of 11005055597 is 79555050011.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 8644164676 + 2360890921 = 92974^2 + 48589^2 .

It is a cyclic number.

It is not a de Polignac number, because 11005055597 - 26 = 11005055533 is a prime.

It is a super-2 number, since 2×110050555972 (a number of 21 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 11005055597.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11005055297) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5502527798 + 5502527799.

It is an arithmetic number, because the mean of its divisors is an integer number (5502527799).

Almost surely, 211005055597 is an apocalyptic number.

It is an amenable number.

11005055597 is a deficient number, since it is larger than the sum of its proper divisors (1).

11005055597 is an equidigital number, since it uses as much as digits as its factorization.

11005055597 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 39375, while the sum is 38.

The spelling of 11005055597 in words is "eleven billion, five million, fifty-five thousand, five hundred ninety-seven".