Base | Representation |
---|---|
bin | 1010000000100101000011… |
… | …0000001001001010000111 |
3 | 1102222001222121211121221021 |
4 | 2200021100300021022013 |
5 | 2420301331104310210 |
6 | 35223353310332011 |
7 | 2214042446102560 |
oct | 240112060111207 |
9 | 42861877747837 |
10 | 11005061010055 |
11 | 3563247047752 |
12 | 1298a307ba007 |
13 | 61aa07ac4568 |
14 | 2a090d799167 |
15 | 141400b62bda |
hex | a0250c09287 |
11005061010055 has 16 divisors (see below), whose sum is σ = 15117037447680. Its totient is φ = 7534136375712.
The previous prime is 11005061010037. The next prime is 11005061010107. The reversal of 11005061010055 is 55001016050011.
It is a cyclic number.
It is not a de Polignac number, because 11005061010055 - 229 = 11004524139143 is a prime.
It is a super-2 number, since 2×110050610100552 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 253960819 + ... + 254004148.
It is an arithmetic number, because the mean of its divisors is an integer number (944814840480).
Almost surely, 211005061010055 is an apocalyptic number.
11005061010055 is a deficient number, since it is larger than the sum of its proper divisors (4111976437625).
11005061010055 is an equidigital number, since it uses as much as digits as its factorization.
11005061010055 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 507965598.
The product of its (nonzero) digits is 750, while the sum is 25.
Adding to 11005061010055 its reverse (55001016050011), we get a palindrome (66006077060066).
The spelling of 11005061010055 in words is "eleven trillion, five billion, sixty-one million, ten thousand, fifty-five".
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