11005145113 has 2 divisors, whose sum is σ = 11005145114. Its totient is φ = 11005145112.

The previous prime is 11005145077. The next prime is 11005145117. The reversal of 11005145113 is 31154150011.

11005145113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 10354487049 + 650658064 = 101757^2 + 25508^2 .

It is a cyclic number.

It is not a de Polignac number, because 11005145113 - 2²⁵ = 10971590681 is a prime.

It is a super-2 number, since 2×11005145113² (a number of 21 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (11005145117) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5502572556 + 5502572557.

It is an arithmetic number, because the mean of its divisors is an integer number (5502572557).

Almost surely, 2^11005145113 is an apocalyptic number.

It is an amenable number.

11005145113 is a deficient number, since it is larger than the sum of its proper divisors (1).

11005145113 is an equidigital number, since it uses as much as digits as its factorization.

11005145113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 300, while the sum is 22.

Adding to 11005145113 its reverse (31154150011), we get a palindrome (42159295124).

The spelling of 11005145113 in words is "eleven billion, five million, one hundred forty-five thousand, one hundred thirteen".