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110053907 is a prime number
BaseRepresentation
bin1101000111101…
…00101000010011
321200002022120122
412203310220103
5211133211112
614530500455
72504304605
oct643645023
9250068518
10110053907
1157139147
1230a3472b
1319a53a72
141088b175
1599dd872
hex68f4a13

110053907 has 2 divisors, whose sum is σ = 110053908. Its totient is φ = 110053906.

The previous prime is 110053849. The next prime is 110053949. The reversal of 110053907 is 709350011.

It is a strong prime.

It is an emirp because it is prime and its reverse (709350011) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 110053907 - 26 = 110053843 is a prime.

It is a super-2 number, since 2×1100539072 = 24223724891929298, which contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (110053807) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55026953 + 55026954.

It is an arithmetic number, because the mean of its divisors is an integer number (55026954).

Almost surely, 2110053907 is an apocalyptic number.

110053907 is a deficient number, since it is larger than the sum of its proper divisors (1).

110053907 is an equidigital number, since it uses as much as digits as its factorization.

110053907 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 945, while the sum is 26.

The square root of 110053907 is about 10490.6580823130. The cubic root of 110053907 is about 479.2202429453.

The spelling of 110053907 in words is "one hundred ten million, fifty-three thousand, nine hundred seven".