Base | Representation |
---|---|
bin | 10000000000111110100… |
… | …011000010100001100111 |
3 | 10220012201222200112210221 |
4 | 100000332203002201213 |
5 | 121012422104004201 |
6 | 2201331333425211 |
7 | 142340633103445 |
oct | 20007643024147 |
9 | 3805658615727 |
10 | 1100561000551 |
11 | 394821aa2011 |
12 | 15936779b207 |
13 | 7ca2309a86c |
14 | 3b3a5bbbb95 |
15 | 1d964d684a1 |
hex | 1003e8c2867 |
1100561000551 has 4 divisors (see below), whose sum is σ = 1100648868192. Its totient is φ = 1100473132912.
The previous prime is 1100561000549. The next prime is 1100561000563. The reversal of 1100561000551 is 1550001650011.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1100561000551 - 21 = 1100561000549 is a prime.
It is a super-2 number, since 2×11005610005512 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1100561004551) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 43915030 + ... + 43940083.
It is an arithmetic number, because the mean of its divisors is an integer number (275162217048).
Almost surely, 21100561000551 is an apocalyptic number.
1100561000551 is a deficient number, since it is larger than the sum of its proper divisors (87867641).
1100561000551 is an equidigital number, since it uses as much as digits as its factorization.
1100561000551 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 87867640.
The product of its (nonzero) digits is 750, while the sum is 25.
Adding to 1100561000551 its reverse (1550001650011), we get a palindrome (2650562650562).
The spelling of 1100561000551 in words is "one trillion, one hundred billion, five hundred sixty-one million, five hundred fifty-one", and thus it is an aban number.
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