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11006465603473 is a prime number
BaseRepresentation
bin1010000000101010010001…
…1110001111011110010001
31102222012121111211100212201
42200022210132033132101
52420312220143302343
635224144523523201
72214122322666244
oct240124436173621
942865544740781
1011006465603473
1135638a799355a
121299163089501
1361ab9cac0a22
142a0a0414525b
1514148411394d
hexa02a478f791

11006465603473 has 2 divisors, whose sum is σ = 11006465603474. Its totient is φ = 11006465603472.

The previous prime is 11006465603447. The next prime is 11006465603489. The reversal of 11006465603473 is 37430656460011.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 5994383445649 + 5012082157824 = 2448343^2 + 2238768^2 .

It is an emirp because it is prime and its reverse (37430656460011) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-11006465603473 is a prime.

It is a super-2 number, since 2×110064656034732 (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (11006465606473) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5503232801736 + 5503232801737.

It is an arithmetic number, because the mean of its divisors is an integer number (5503232801737).

Almost surely, 211006465603473 is an apocalyptic number.

It is an amenable number.

11006465603473 is a deficient number, since it is larger than the sum of its proper divisors (1).

11006465603473 is an equidigital number, since it uses as much as digits as its factorization.

11006465603473 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1088640, while the sum is 46.

The spelling of 11006465603473 in words is "eleven trillion, six billion, four hundred sixty-five million, six hundred three thousand, four hundred seventy-three".